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Title: If 25.0 mL of 0.100 M lithium iodide reacts completely with aqueous mercury(II) Post by: OldSpice on Dec 8, 2014 If 25.0 mL of 0.100 M lithium iodide reacts completely with aqueous mercury(II) nitrate, what is the mass of HgI2 (454.39 g/mol) precipitate?
2 LiI(aq) + Hg(NO3)2(aq) ? HgI2(s) + 2 LiNO3(aq) A) 0.568 g B) 1.14 g C) 2.27 g D) 2.75 g E) 5.50 g Title: Re: If 25.0 mL of 0.100 M lithium iodide reacts completely with aqueous mercury(II) Post by: Electric on Dec 11, 2014 Content hidden
Title: Re: If 25.0 mL of 0.100 M lithium iodide reacts completely with aqueous mercury(II) Post by: OldSpice on Dec 14, 2014 Perfect!
..Thank you so much for your support Title: Re: If 25.0 mL of 0.100 M lithium iodide reacts completely with aqueous mercury(II) Post by: Electric on Dec 14, 2014 My pleasure
Title: Re: If 25.0 mL of 0.100 M lithium iodide reacts completely with aqueous mercury(II) Post by: Axel Funes on Jul 31, 2020 Thank you!
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