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Other Fields Homework Help Other Topic started by: OldSpice on Dec 8, 2014



Title: If 1.020 g of KHC8H4O4 (204.23 g/mol) is completely neutralized with 0.200 M KOH
Post by: OldSpice on Dec 8, 2014
If 1.020 g of KHC8H4O4 (204.23 g/mol) is completely neutralized with 0.200 M KOH, what volume of potassium hydroxide is required?
   KHC8H4O4(aq) + KOH(aq) ? K2C8H4O4(aq) + 2 H2O(l)
A) 12.5 mL
B) 20.0 mL
C) 25.0 mL
D) 40.0 mL
E) 50.0 mL


Title: Re: If 1.020 g of KHC8H4O4 (204.23 g/mol) is completely neutralized with 0.200 M KOH
Post by: Electric on Dec 11, 2014
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Title: Re: If 1.020 g of KHC8H4O4 (204.23 g/mol) is completely neutralized with 0.200 M KOH
Post by: OldSpice on Dec 14, 2014
Perfect!

..Thank you so much for your support


Title: Re: If 1.020 g of KHC8H4O4 (204.23 g/mol) is completely neutralized with 0.200 M KOH
Post by: Electric on Dec 14, 2014
My pleasure


Title: BFSF: If 1.020 g of KHC8H4O4 (204.23 g/mol) is completely neutralized with 0.200 M KOH
Post by: Reuben Sequeira on May 22, 2023
Help! The answer is missing an explanation...