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Title: Solving logarithmic equations Post by: Mathguy3000 on Jul 24, 2018 Log of base 2 (2x+4) - log of base 2 (x-1)= 3
Title: Re: Solving logarithmic equations Post by: bio_man on Jul 24, 2018 Done:
The two logs both have the same base, so you can apply the log rules: \(\log _2\left(2x+4\right)-\log _2(x-1)=3\) \(\log _2\left(\frac{2x+4}{x-1}\right)=3\) \(\frac{2x+4}{x-1}=2^3\) \(2x+4=8\left(x-1\right)\) \(2x+4=8x-8\) \(12=6x\) \(2=x\) |