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Title: Resistors in Series and Parallel Post by: astuckey on Sep 12, 2018 Three 12 Ω resistors are connected in parallel and then connected to a 6.0 V battery. Find the resulting current.
Show your work (formula, substitution, answer rounded correctly and with the appropriate unit. This is a two part question. Title: Re: Resistors in Series and Parallel Post by: gcd99br on Sep 12, 2018 R1-R3= 12 Ω
1/RT = 1/12 Ω + 1/12 Ω + 1/12 Ω = 3/12 Ω RT= 12/3 = 4 Ω V= 6.0 V I= ? V=IR I= V/R I= (6.0) / (4) I= 1.5 A Current through all resistors= 1.5 A Current through each resistor= 1.5/3 = 0.5 A |