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Title: Electric Power Transmission Post by: astuckey on Sep 12, 2018 A 100 MW power station generates energy at 26.0 kV. The power lines must carry only 200 A of current to be efficient enough. To what voltage must the potential be increased?
Show your work (formula, substitution, answer rounded correctly and with the appropriate unit). Title: Re: Electric Power Transmission Post by: bio_man on Sep 12, 2018 power = voltage \(\times \) current
\(P=VI\) We are told the power (100MW = 100x10⁶ W) We are told the current we want (I = 200A) So we can find the voltage we want Rearrange the formula to get V isolated V = P/I Put the value in V = 100x10⁶ / 200 V = 5 x10⁵ V If you want the answer in kV, divide by 1000 V = 500kV (The value of 26.0kV is not needed here.) |