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Title: How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas? Post by: Asfian on Oct 11, 2018 How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas?
2 Ca(OH)2(aq) + 2 Cl2(g) Ca(OCl)2(aq) + CaCl2(s) + 2 H2O(l) A) 0.00395 g B) 0.00789 g C) 0.0158 g D) 0.0253 g Title: How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas? Post by: spsjr15 on Oct 11, 2018 Content hidden
Title: Re: How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 ... Post by: maddiecothran on Nov 14, 2019 thanks
Title: Re: How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 ... Post by: Erik Thibault on Dec 16, 2019 thank you :)
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Title: Re: How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 ... Post by: Addison Elliott on Oct 14, 2020 thank you this was helpful
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