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Title: Delta method versus quotient rule Post by: bio_man on Dec 10, 2018 \(f\left(x\right)=\frac{3}{x^2+1}\)
Applying the quotient rule, notice how the denominator is now squared: \(f'\left(x\right)=\frac{\left(0\right)\left(x^2+1\right)-\left(3\right)\left(2x\right)}{\left(x^2+1\right)^2}\) Simplify: \(f'\left(x\right)=\frac{-6x}{\left(x^2+1\right)^2}\) Title: Re: Delta method versus quotient rule Post by: ryann on Jun 30, 2019 Looks like this is solved. Good work !
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