Title: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: Annlore1345 on Jun 19, 2019 An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What mass ( g ) of KOH was in the original sample?
A)0.129 B)0.190 C)0.173 D)0.207 E)0.215 Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What Post by: bio_man on Jun 19, 2019 Content hidden
Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: bio_man on Jun 19, 2019 Topic updated ^^
Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: Annlore1345 on Jun 19, 2019 Thank you so much, but from where do u get the 56.1 g.
Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: bio_man on Jun 19, 2019 That's the molar mass of NaOH
Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: Annlore1345 on Jun 19, 2019 Ohh ok ok, thanks again
Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: bio_man on Jun 19, 2019 Ohh ok ok, thanks again You're welcome. Let us know if you have any other questions (chem, math, etc) Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What Post by: Annlore1345 on Jun 19, 2019 Hello I was calculating the molar mass and that not the answer that I got. I get 39.99g
Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: bio_man on Jun 19, 2019 Sorry, I meant molar mass of KOH 🤦♂️
Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: Annlore1345 on Jun 19, 2019 Ohh ok it's fine thank you so muchh☺️
Title: Re: An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What ... Post by: Gwen Lyles on Feb 15, 2020 thank you
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