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Title: What is the empirical formula of a compound that is 15.9% boron and 84.1% fluorine? Post by: Jess8219 on May 14, 2020 what is the empirical formula of a compound that is 15.9% boron and 84.1% fluorine?
Title: Re: What is the empirical formula of a compound that is 15.9% boron and 84.1% fluorine? Post by: bio_man on May 14, 2020 15.9% boron > 0.159 and 84.1% fluorine > 0.841
molar mass of B : 10.81 15.9 / 10.81 = 1.4708 84.1 / 18.99 = 4.4286 1.4708 : 4.4286 Divide by lowest term: 1 : 2.91 Or 1:~3 BF3 |