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Title: A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of ... Post by: Jakeshmitty on Mar 21, 2021 A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.831-g sample of the mixture, the mass of precipitate collected is 2.826 g. What is the mass percentage of barium chloride in the mixture? ▸ 82.70% ▸ 73.77% ▸ 43.39% ▸ 65.80% ▸ 13.61% Title: A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of ... Post by: d123 on Mar 21, 2021 Content hidden
Title: Re: A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition ... Post by: Yogen on Dec 2, 2022 A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.988 g sample of the mixture, the mass of precipitate collected is 2.113g. What is the mass percentage of sodium chloride in the mixture?
Title: Re: A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition Post by: jada on Dec 2, 2022 A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.988 g sample of the mixture, the mass of precipitate collected is 2.113g. What is the mass percentage of sodium chloride in the mixture? molar mass of BaCl2 = 208.23 g/mol molar mass of BaSO4 = 233.43 g/mol therefore moles of BasO4 formed = mass/ molar mass 2.113 / 233.34 = 9.05 x 10-3 mol herefore mass of BaCl2 mixture = moles x molar mass = 9.05 x 10-3 mol x 208.23 g/mol = 1.885 g % BaCl2 = (1.885 g / 3.988 g ) x 100 % BaCl2 = 47.2% |