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Title: You have a 10.40-g mixture of table sugar (C12H22O11) and table salt (NaCl). When this mixture is ... Post by: atay3226 on Mar 21, 2021 You have a 10.40-g mixture of table sugar (C12H22O11) and table salt (NaCl). When this mixture is dissolved in 150. g of water, the freezing point is found to be –2.24°C. Calculate the percent by mass of sugar in the original mixture. ▸ 39.0% ▸ 43.8% ▸ 53.9% ▸ 61.0% ▸ none of these are correct Title: You have a 10.40-g mixture of table sugar (C12H22O11) and table salt (NaCl). When this mixture is ... Post by: TheOGFunk on Mar 21, 2021 Content hidden
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