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Title: How many grams of CaCl2 are formed when 15.00 mL of 0.00237 mol L-1 Ca(OH)2(aq) reacts with excess ... Post by: arlinguillen on Jun 23, 2021 How many grams of CaCl2 are formed when 15.00 mL of 0.00237 mol L-1 Ca(OH)2(aq) reacts with excess Cl2 gas?
2 Ca(OH)2(aq) + 2 Cl2(g) → Ca(OCl)2(aq) + CaCl2(s) + 2 H2O(l) ▸ 0.00197 g ▸ 0.00394 g ▸ 0.00789 g ▸ 0.0507 g Title: How many grams of CaCl2 are formed when 15.00 mL of 0.00237 mol L-1 Ca(OH)2(aq) reacts with excess ... Post by: calebmacharia on Jun 23, 2021 Content hidden
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