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Title: Combustion of 493 mg of a hydrocarbon gave 1549 mg CO2 and 633.9 mg H2O. What is the molecular ... Post by: adegob on Jun 27, 2021 Combustion of 493 mg of a hydrocarbon gave 1549 mg CO2 and 633.9 mg H2O. What is the molecular formula if the molecular weight is subsequently found to be 42?
▸ CO2 ▸ CH2 ▸ C6H12 ▸ C2H2O ▸ C3H6 Title: Combustion of 493 mg of a hydrocarbon gave 1549 mg CO2 and 633.9 mg H2O. What is the molecular ... Post by: bali on Jun 27, 2021 Content hidden
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