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Title: Collision network Post by: s.h_math on Nov 25, 2021 A 25 kg turkey is fired from a 1.1x10^3 kg turkey launcher. If the horizontal velocity of the turkey is 325 m/s east, what is the recoil of the launcher?
Hi there, I'm kind of confused on how to solve for the recoil of the launcher, I have to show a step-by-step solution, but not sure how to solve this question. Title: Re: Collision network Post by: duddy on Nov 25, 2021 Another law of conservation of linear momentum problem:
Thankfully, it is being fired horizontally, otherwise the problem would get annoying. Turkey: 25 kg Launcher: 1100 kg Turkey and launcher combined: 1125 kg Initial speed turkey and launcher: 0 m/s Speed of turkey: 325 m/s 1125 kg ( 0 m/s ) = 25 kg ( 325 m/s ) + 1100 kg ( v ) 0 = 8125 kg*m/s + 1100 kg ( v ) Bring 8125 kg*m/s to the left: -8125 kg*m/s = 1100 kg ( v ) Solve for v: -8125 kg*m/s / 1100 kg = v v = -7.4 m/s, which means 7.4 [west]. Title: Re: Collision network Post by: s.h_math on Nov 25, 2021 Do you think you could possibly share the equation to what these numbers were plugged in 1125 kg ( 0 m/s ) = 25 kg ( 325 m/s ) + 1100 kg ( v )? Thanks!
Title: Re: Collision network Post by: duddy on Nov 25, 2021 Yes, of course. Remember I made reference to the law of conservation of linear momentum
I used this law here initial: https://biology-forums.com/index.php?topic=1998690.msg5283630#msg5283630 The main idea is that momentum = momentum, and depending on the situation, you may have to modify what you place on the left-side and what is placed on the right side. It's not a one-size fits all situation. How's that? |