Title: The position of an object in free fall near the surface of the plane where the acceleration due to ...
Post by: MrJokeNobidy on Dec 9, 2021
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The position of an object in free fall near the surface of the plane where the acceleration due to gravity has a constant magnitude of g (length-units)/sec2 is given by the equation:
s = -
gt2 + v0t + s0, where s is the height above the earth, v0 is the initial velocity, and s0 is the initial height. Give the initial value problem for this situation. Solve it to check its validity. Remember the positive direction is the upward direction.
▸
= g , s '(0) = v0, s(0) = s0
▸ = -gt , s(0) = s0
▸ = -g , s '(0) = v0, s(0) = s0
▸ = -g
The position of an object in free fall near the surface of the plane where the acceleration due to gravity has a constant magnitude of g (length-units)/sec2 is given by the equation:
s = -
gt2 + v0t + s0, where s is the height above the earth, v0 is the initial velocity, and s0 is the initial height. Give the initial value problem for this situation. Solve it to check its validity. Remember the positive direction is the upward direction.▸
= g , s '(0) = v0, s(0) = s0▸
= -gt , s(0) = s0▸
= -g , s '(0) = v0, s(0) = s0▸
= -gTitle: The position of an object in free fall near the surface of the plane where the acceleration due to ...
Post by: zsc999 on Dec 9, 2021
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