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Title: A 50.0-kg box is resting on a horizontal floor. A force of 250 N directed at an Post by: ppk on Apr 14, 2012 A 50.0-kg box is resting on a horizontal floor. A force of 250 N directed at an angle of 30.0° below the horizontal is applied to the box. The coefficient of static friction between the box and the surface is 0.400. What is the force of friction on the box?
A) 31.9 N B) 196 N C) 217 N D) 246 N E) 616 N Title: Re: A 50.0-kg box is resting on a horizontal floor. A force of 250 N directed at an Post by: robertling on Apr 15, 2012 C
Title: Re: A 50.0-kg box is resting on a horizontal floor. A force of 250 N directed at an Post by: tibbylee on Apr 19, 2012 Ff = m(?)
Fr = m(9.81) Fr = 490.5 N Fy = 250sin30° Fy = 125 N F = 125 + 490.5 N = 615.5 N Ff = 615.5(0.400) D. |