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Title: 700uL 1:75 solution. Can be used to make 500uL 1:100 and 500uL 1:125 solutions? Post by: O.G. Mann on Apr 21, 2022 For Vf=500 and DF=100, Vi=5 and Vf=500 and DF=125, Vi=4, 9uL of the 700uL 1:75 solution would be required for the two 500uL solutions. The initial solution concentration would be 100% for the two additional dilutions. They are not serial. Am I missing something?
Title: Re: 700uL 1:75 solution. Can be used to make 500uL 1:100 and 500uL 1:125 solutions? Post by: bio_man on Apr 21, 2022 I'll try to sort this out for you.
500uL at 1:100 means that you start with a volume of 5 μL at 100% concentrations, which you add 495 μL of solvent to make 500 μL in total. Df = Vf / Vi Df = 500 μL / 5 μL Df = 100 Thus, 1:100 dilution. Using C1V1 = C2V2, since the initial 5 μL at 100% concentration, then: (1)*(5μL) = C2*(500μL) 5μL/500μL = C2 = 0.01 Thus, the new concentration is 0.01 |