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Title: A stone is thrown upwards with an initial velocity of 25m/s at an angle of 30 degree to the ground ... Post by: Surayan on Dec 20, 2022 A stone is thrown upwards with an initial velocity of 25m/s at an angle of 30 degree to the ground then find how long will it take between when the stone was thrown and when it comes back to the ground?
Title: Re: A stone is thrown upwards with an initial velocity of 25m/s at an angle of 30 degree to the ground ... Post by: nas12 on Dec 20, 2022 The time taken for the stone to come back to the ground can be calculated using the equation:
t = 2v sin(θ) / g where v is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity (9.8 m/s2). Therefore, the time taken for the stone to come back to the ground is: t = 2(25 m/s) sin(30°) / 9.8 m/s2 t = 5.1 s |