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Title: Tito and Michael put 1200 joules of work into pushing a box up a ramp, but only 300 joules of work ... Post by: gcollins97 on Mar 24, 2023 Tito and Michael put 1200 joules of work into pushing a box up a ramp, but only 300 joules of work is output for moving the box. What is the efficiency of the ramp?
Title: Re: Tito and Michael put 1200 joules of work into pushing a box up a ramp, but only 300 joules of work ... Post by: Mat RT on Mar 24, 2023 The efficiency of the ramp can be calculated using the formula:
Efficiency = (Output Work / Input Work) x 100% Here, the input work is 1200 joules and the output work is 300 joules. Efficiency = (300 / 1200) x 100% Efficiency = 0.25 x 100% Efficiency = 25% Therefore, the efficiency of the ramp is 25%. This means that only 25% of the work put into pushing the box up the ramp is actually output as useful work in moving the box. The remaining 75% of the work is lost due to friction, air resistance, and other factors. |