Title: If a machine requires an input of 5000 Joules of input to do 2500 Joules of work, what is the ...Post by: jjboy817 on Mar 24, 2023
If a machine requires an input of 5000 Joules of input to do 2500 Joules of work, what is the efficiency of the machine?
Title: Re: If a machine requires an input of 5000 Joules of input to do 2500 Joules of work, what is the ...Post by: htnguy16 on Mar 24, 2023
Efficiency is defined as the ratio of the output work to the input energy, expressed as a percentage. In this case, the machine does 2500 Joules of work using an input of 5000 Joules. Therefore, the efficiency of the machine is:
Efficiency = (Output work/Input energy) x 100% Efficiency = (2500/5000) x 100% Efficiency = 50% So the efficiency of the machine is 50%. |