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Title: The capacitive network shown is assembled with initially uncharged capacitors. A Post by: ricotico8 on Jan 30, 2015 The capacitive network shown is assembled with initially uncharged capacitors. A potential difference, is applied across the network. The switch S in the network is kept open throughout. In Figure 18.12, the total energy stored in the seven capacitors, in mJ, is closest to:
144 96 72 120 48 Title: Re: The capacitive network shown is assembled with initially uncharged capacitors. A Post by: bio_man on Jan 31, 2015 the 4μF, 8μF and 12μF are in parallel so the equivalent capacitance is
C1 = 4μF + 8μF + 12μF C1 = 24μF now C1 and the 6μF are in series so the equivalent capacitance C2 is 1/C2 = 1/24μF + 1/6μF C2 = 4.8 μF the 9μF and 15μF are in parallel so the equivalent capacitance C3 is C3 = 9μF + 15μF C3 = 24μF now Vab = Vac + Vcb 100 V = q1/C3 + q1/16μF 100 V = q1(1/24μF + 1/16μF) q1 = 960 μC Vab = Vad + Vdb 100 V = q2/6μF + q2/C1 100 V = q2(1/6μF + 1/24μF) q2 = 480 μC and Vbc = Vcd + Vdb Vcd = Vbc - Vdb Vcd = 960C/16μF - 480μC/24μF Vcd = 40 V |