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Title: How many grams of BaCl2 are formed when 35.00 mL of 0.00237 M Ba(OH)2 reacts with excess Cl2 gas?2 B Post by: Whelan on May 5, 2015 How many grams of BaCl2 are formed when 35.00 mL of 0.00237 M Ba(OH)2 reacts with excess Cl2 gas?
2 Ba(OH)2(aq) + 2 Cl2(g) → Ba(OCl)2(aq) + BaCl2(s) + 2 H2O(l) A) 0.00864 g B) 0.0173 g C) 0.0346 g D) 0.0829 g Title: Re: How many grams of BaCl2 are formed when 35.00 mL of 0.00237 M Ba(OH)2 reacts with excess Cl2 gas Post by: hbutler2 on May 25, 2015 Content hidden
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