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Title: Magnesium sulfate reacts with barium chloride according to the following balance Post by: Jofish on May 29, 2015 Magnesium sulfate reacts with barium chloride according to the following balanced equation. If 1.20 g of magnesium sulfate is allowed to react with 10.0 g of barium chloride in a water solution, what is the theoretical yield of barium sulfate?
MgSO4(aq) + BaCl2(aq) Right Arrow BaSO4(s) + MgCl2(aq)
Title: Re: Magnesium sulfate reacts with barium chloride according to the following balance Post by: psyche360 on May 29, 2015 See if this helps:
Similar Question MgSO4(aq) + BaCl2(aq) → BaSO4(s) + MgCl2(aq) Magnesium sulfate reacts with barium chloride according to the following balanced equation. How many moles of barium sulfate are formed from 10.0 g of magnesium sulfate? MgSO4(aq) + BaCl2(aq) → BaSO4(s) + MgCl2(aq) 1.00 mol 0.0831 mol 0.166 mol 0.500 mol 0.200 mol Possible answer: From the balanced equation: 1mol MgSO4 will produce 1 mol BaSO4 Molar mass MgSO4120.4g/mol 10g MgSO4 = 10/120.4 = 0.0831 mol MgSO4 This will produce 0.0831 mol BaSO4 - choice b) correct. |