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Title: In a dihybrid cross between a parent that is a double heterozygote (AaBb) and a parent that is homozygous? Post by: mike13m on May 7, 2012 recessive (aabb), how many different phenotypes will there be in their offspring. List the specific amounts. If you can put a Punnet Square in that would be great!
Title: In a dihybrid cross between a parent that is a double heterozygote (AaBb) and a parent that is homozygous? Post by: lgood4 on May 7, 2012 The possible gamete genotypes of the heterozygote are: AB, Ab, aB, ab
The possible gamete genotypes of the homozygous recessive are: ab If these are crossed (I have done a punnet square - see the link below) you end up with: 25% AaBb, 25% Aabb, 25% aaBb, 25% aabb Which means there are four different offspring phenotypes, with equal amounts of each. Punnet square: http://i90.photobucket.com/albums/k270/hannahsutlow/Punnet.jpg Hope this helps! |