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Title: How to factor quadratics with? Post by: Fedorfan76 on Aug 28, 2012 5x squared + 2x + 3
How to factor with a number on the first part? I am stuck when there is a number in the first part. The problem is just an example. It may not be factorable. Title: How to factor quadratics with? Post by: !JRon@n on Aug 28, 2012 5x^2+2x+3 I think not+3 but -3 so
5x^2+2x-3=(5x-3)(x+1) Title: How to factor quadratics with? Post by: JulieA on Aug 28, 2012 Content hidden
Title: How to factor quadratics with? Post by: rjframe on Aug 28, 2012 Say, it is of the form:
ax² + bx + c = 0,.................(1), where a, b and c are constants. (i) Multiply "a" and "c"& factorize the product (ac) into ALL POSSIBLE factors. (ii) Amongst all these, choose combination of a pair of those two factors whose sum or difference is b. Let's say "m" and "n", so that b = m ± n, (of course mn = ac) and write (1) as: ax² + (m ± n) x + c = 0 or ax² + mx ± n x + c = 0. (iii) Group as under & take highest common factor in each group: {Ist} + {IInd} (ax² + mx) ± (n x + c) = 0. Say it is like: px(rx + s) + q(rx + s) = 0, where p, q, r, and s are constants. Then, finally, factors of the quadratic (1) will be: (px + q)(rx + s) = 0. Title: How to factor quadratics with? Post by: fireman2101 on Aug 28, 2012 just get its factors..for your example, it just has one pair of factor, 5x and x..
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