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Title: How to find the maximum and minimum value of this cubic function? Post by: fiveftfury on Sep 2, 2012 y=x^3 - 8
I know it's simple, but I do I even try to get a derivative out of it? Title: How to find the maximum and minimum value of this cubic function? Post by: fives on Sep 2, 2012 OK Ameh... if you take the derivative of it you just end up with 3x^2 =0 so 0 should be one of your extrema but it is just an inflection or saddle point. If you factor this cubic you see that (x-2)*(x^2 +2x +4) . But this only tells you that at x = 2 y = 0. Graphing it shows you that the max is +oo and the min is -oo.
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