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Title: Frequency of gametes and phenotypes from genetic map Post by: thesurgeon on Nov 15, 2015 Consider the genetic map below of loci a-g, where the distance between loci are indicated in map units.
a-5-b-20-c-10-d-2-e-25-f-1-g a) Calculate the frequency of ac gametes from an Ac/aC genotype. b) BcE from bce/BCE c) bFG from bfg/BFG d) the frequency of BCD/Bcd from bCd/BcD x BCd/BcD e) the frequency of aBcDeFg/aBcDeFg progeny from a mating of ABcDefg/abCdEFG x AbCDeFg/aBcDEfG ---------- What I tried to do: a) recombination must happen between A and c in order to get the phenotype AC/ac , therefore the frequency is the distance between a and c which is 25u , so the frequency of the gamete is 25% (or should it be 25% * 50% because we multiply by the chance of getting the ac gamete?) b)2 recombinations must happen between b and c & c and e , therefore the frequency is 20%*(10+2)% = 2.4% (or should it be 2.4% * 50% for the same reason as part a ?) c) one recombination between b and f -> 20+10+2+25= 57% (or 57% * 50% ? ) d) and e) How is it possible to have recombinations in both parents? I don't see any way to solve it without having recombinations in both parents... |