Title: Physical Chemistry - Chemical Equilibrium? Post by: asaf on May 27, 2011 Under the conditions of: 400 celsius degrees, 350 barr We mix Nitrogen and Hidrogen at a rate of 3:1 (correspondly) In equilibrium we get that 50% of the product is Amonia N2 (g) + 3H2 (g) -> 2NH3 (g) A) Calculate the equilibtium constant of pressure: Kp ? B) Calculate the free Gibbs energy under that conditions? [Kj/mol] Title: Re: Physical Chemistry - Chemical Equilibrium? Post by: chemb on May 27, 2011 Your expression is as follows: Kp= [NH3]2/[N2][H2]3
Gibbs Free Energy: \({\Delta}\)G = \({\Delta}\)H - T\({\Delta}\)S |