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Title: The percent by mass octane is quantified for an organic sample via GC using decane as the Post by: Da4gotten on Dec 7, 2015 The percent by mass octane is quantified for an organic sample via GC using decane as the
internal standard. A GC vial containing 0.5023 grams organic sample and 0.2384 grams decane is prepared and analyzed, returning peak areas of 119,993 for octane and 83755 for decane. If a response factor of 2.50 from previous work analyzing octane with a decane internal standard is used, what is the percent by mass octane in the organic sample? Please, I need help. using formula: area of analyte signal/mass of analyte = F(area of internal standard signal/mass of internal standard signal) (11,993/X)=(2.50)(83755/0.2384g) = 0.1366 g octane /0.5023g organic sample x 100 = 27% Is this correct? Title: Re: The percent by mass octane is quantified for an organic sample via GC using decane as the Post by: bolbol on May 26, 2017 Content hidden
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