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Title: What is the minimum volume of the flask in order that no liquid water be present in the flask? Post by: ilkat on Sep 14, 2012 A sealed flask contains 0.45g of water at 28 degrees C . The vapor pressure of water at this temperature is 28.36 mmHg. What is the minimum volume of the flask in order that no liquid water be present in the flask?
Title: What is the minimum volume of the flask in order that no liquid water be present in the flask? Post by: illmatic118 on Sep 14, 2012 You can just use the ideal gas law to calculate the volume required to contain that amount of water at that temperature and pressure:
moles H2O = 0.45 g / 18.0 g/mol = 0.025 mol P = 28.36 mmHg / 760 mmHg/atm = 0.0373 atm T = 28 + 273 = 301 K R = 0.0821 Latm/molK Plug those into the ideal gas law: PV = nRT and solve for V. Your volume will have units of Liters. 0.0373 atm V = 0.025 mol (0.0821 Latm/molK) 301K V = 16.6 L |