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Title: Calculate the mass of water produced when 6.11 g of butane reacts with excess ox Post by: ajb0959 on Mar 12, 2016 need help quick
Title: Re: Calculate the mass of water produced when 6.11 g of butane reacts with excess ox Post by: bio_man on Mar 13, 2016 Similar Question Calculate the mass of water produced when 6.11 g of butane reacts with excess oxygen. Express your answer to three digits and include the appropriate units. C4H10 +(13/2)O2---------> 4CO2+5H2O ACCORDING TO BALANCED EQUATION 58.12g/mole of butane gives 5*18=90g of H2O so 6.11g of butane gives=? grams of H2O =(6.11*90)/58.12=9.46g of H2O. |