Biology Forums - Study Force

Science-Related Homework Help Mathematics Topic started by: victoria1 on Apr 28, 2016



Title: Use Leonardo’s table of chords to solve the following...
Post by: victoria1 on Apr 28, 2016
Use Leonardo's table of chords to solve the following: Suppose a given chord in a circle of diameter 10 is 8 rods, 3 feet, 16 2/7 unciae. Find the length of the arc cut off by the chord.


Title: Re: Use Leonardo’s table of chords to solve the following...
Post by: taige on Apr 30, 2016
FOLLOW THIS Arc length= rx, where x = angle in radians. 60 = 12x, x = 5 A radius will bisect the chord at a 90 degree angle and also bisect the angle at the centre, so sin (x/2) = 1/2 chord / radius 12 sin 2.5 = 1/2 chord, chord = 24 sin(2.5) = 14.36 You can do the second one by realizing that the two large triangles have a side in common. You then find common size angles by knowing that all the angles in any triangle add up to 180. Just work with the combinations and you can find two or more equal angles in the two large triangles. Two angles and a side equal means the triangles are equal, so you prove it that way.


Title: Re: Use Leonardo’s table of chords to solve the following...
Post by: sem1991 on Apr 30, 2016
Content hidden


Title: Re: Use Leonardo’s table of chords to solve the following...
Post by: Anonymous1380 on Oct 11, 2020
.


Title: Re: Use Leonardo’s table of chords to solve the following...
Post by: assholemcgee on Nov 11, 2020
 bruh


Title: Re: Use Leonardo’s table of chords to solve the following...
Post by: Sarah Landgraf on Nov 12, 2020
...


Title: Re: Use Leonardo’s table of chords to solve the following...
Post by: Burt Z. on Jan 4, 2021
I had this same question! I am stuck because I can't figure out how to read the table and it doesn't explain in the book...


Title: Re: Use Leonardo’s table of chords to solve the following...
Post by: bio_man on Jan 4, 2021
I had this same question! I am stuck because I can't figure out how to read the table and it doesn't explain in the book...

If you still need help, start a new topic. Plenty of experts to help you through this