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Title: How many moles of KOH are contained in 750 mL of 5.00 M KOH solution? Post by: juliechem on May 2, 2016 molarity = moles solute/liters solution
mole KOH= 5.00 M KOH x .75mL/.75mL Title: Re: How many moles of KOH are contained in 750 mL of 5.00 M KOH solution? Post by: zazou on May 10, 2016 5.00 M = 5.00 mol/L
750 mL = 0.750 L Therefore, 5.00 mol/L x 0.750 L = 3.75 mol Title: Re: How many moles of KOH are contained in 750 mL of 5.00 M KOH solution? Post by: itheaker on May 31, 2016 Number of moles (n) is given by the formula n = (c x V)/1000
where c = concentration in M (or mol/L) and V = volume of solution in mL Hence, n = (5 x 750)/1000 = 3.75 mol. |