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Title: Magnesium sulfate reacts with barium chloride according to the following balanced equation. If 1.20 ... Post by: uzmaali3 on Oct 15, 2016 Magnesium sulfate reacts with barium chloride according to the following balanced equation. If 1.20 g of magnesium sulfate is allowed to react with 10.0 g of barium chloride in a water solution, what is the theoretical yield of barium sulfate?
2.08 g 1.20 g 10.0 g 2.33 g 23.3 g Title: Re: Magnesium sulfate reacts with barium chloride according to the following balanced equation. If ... Post by: Laser_3 on Oct 16, 2016 Hi,
MgSO4 + BaCl2 → MgCl2 + BaSO4 Assuming MgSO4 is excess: (10/208.23)*233.43 = 11.2 g BaSO4 Assuming BaCl2 is excess : (1.2/120.366)*233.43 = 2.33 g BaSO4 You can get maximum of 2.33g BaSO4 with the stated conditions. Hope this helps, Title: Re: Magnesium sulfate reacts with barium chloride according to the following balanced equation. If ... Post by: leesajohnson on Oct 27, 2016 MgSO4(aq) + BaCl2(aq) → MgCl2(aq) + BaSO4(s)
Complete ionic equation: Mg^2+(aq) + SO4^2-(aq) + Ba^2+(aq) + 2 Cl^-(aq) → Mg^2+(aq) + 2 Cl^-(aq) + BaSO4(s) Net ionic equation: Ba^2+(aq) + SO4^2-(aq) → BaSO4(s) Answer=2.33g BaSO4 |