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Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: SAMH on Jan 8, 2013 4) In flowers, blue colour is dominant over white petal colour.
The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: A) white and black B) Bb and bb C) Bb and white D) BB and bb Hint for Question 4: (a) bb, the same lower case (b) BB, pure is the same as homozygous (c) Bb, heterozygous means one of each (d) bb, the recessive can only be written in one way (e) BB, genotype is the letters, the gene formula (f) blue; heterozygous is added to distract you Locate the Logic word: phenotype THUMBNAIL #1 _____________________________ _____________________________ ________________________ 5) In a wild plant, white flowers are dominant while red is recessive. The phenotype of a homozygous white flower and the genotype of a red flower, respectively, is: A) Ww and WW B) WW and white C) white and Ww D) white and ww Hint for Question 5: (a) ww, any allele letters as lower case (b) Ww, heterozygous; letters must be different (c) WW, homozygous; letters must be the same (d) red; phenotype! (e) an impossibility: if red it has to be ww, homozygous; if it is heterozygous Ww, then it can't be red THUMBNAIL #2 _____________________________ _____________________________ ________________________ 6) If green is dominant to clear seed colour in a plant, then a cross between two plants that are heterozygous for green seed colour can be represented by: A) P1 = Gg x GG B) P1 = GG x GG C) P1 = Gg x Gg D) P1 = GG x gg Hint for Question 6: (a) P1 = ss x Ss (b) P1 = BB x bb (c) P1 = bb x Bb Information: Once symbols are assigned, the next step is to use the information to correctly form the gene formula (genotype) of the parents. Please practice making the following parents. Before you attempt the multiple choice question check the Hint to evaluate your answers. a) Make the parent generation of the homozygous tall tree pollinated by a heterozygous short tree. Shortness is dominant. b) A yellow flower is recessive. Write the parent generation in a cross between homozygous blue and a yellow flower. c) Brown hair is dominant to red hair. Make the parent generation between a red haired mother and a heterozygous brown haired father. _____________________________ _____________________________ ________________________ 9) When conducting his research into the genetics of garden peas, Gregor Mendel crossed true-breeding, yellow-seeded plants with true-breeding, green-seeded plants. He observed that all the F1 generation had yellow seeds. In the F1 generation, the allele for yellow seeds would have been found in: A) about 50% of the female gametes and 50% of the male gametes produced by F1 plants B) all the female gametes and none of the male gametes produced by the F1 plants C) none of the male or female gametes produced by the F1 plants D) all the male gametes and none of the female gametes produced by the F1 plants _____________________________ _____________________________ ________________________ 11) If (Q) represents the gene for a dominant trait and (q) is the recessive allele, and if Qq mates with qq, then: A) 50% of the offspring will be recessive B) all offspring will be of the dominant trait C) all the offspring will be of the recessive trait D) 75% of the offspring will be of the dominant trait _____________________________ _____________________________ ________________________ 12) If two offspring result from the cross Zz x Zz, what is the probability that both will have the same genotype ZZ? A) 1/4 B) 1/8 C) 1/16 D) 1/2 _____________________________ _____________________________ ________________________ 13) If a short pea plant (recessive) is self-pollinating, then the phenotype of the offspring will be: A) 0% short B) 3:1; 3 tall:1 short C) 50 / 50; half short / half tall D) 100% short _____________________________ _____________________________ ________________________ In birds, black feathers are dominant over white feathers. A black hen is mated to a black rooster. Her eggs were saved. Forty-two chicks hatched in an incubator: thirty-one were black and eleven were white. The gene formulas for the two parents and their offspring are: A) P1 = Bb x bb ; F1 genotypes: Bb, bb, Bb, bb B) P1 = BB x Bb_; F1 genotypes: BB, BB, BB C) P1 = BB x bb ; F1 genotypes: BB, bb, Bb D) P1 = Bb x Bb ; F1 genotypes: BB, bb, Bb _____________________________ _____________________________ ________________________ 15) Numerical Response In the crossing genotype 1 with genotype 2, in what proportion of offspring would the recessive phenotype appear? Record your answer as a value from 0 to 1, rounded to two significant digits. Answer: THUMBNAIL #3 _____________________________ _____________________________ ________________________ 16) Numerical Response Choose the correct genotype number for each description of an offspring. Genotype number: ____________ ____________ ____________ ____________ Offspring Description: Homozygous Genotype similar to Heterozygous Recessive genotype one of the parents genotype phenotype THUMBNAIL #4 _____________________________ _____________________________ ________________________ 17) Gray eyes are inherited as a recessive trait. Two brown-eyed individuals had a gray-eyed offspring. Which of the above crosses would result from the genotype of the parents? A) A. B) B. C) C. D) D. Hint for Question 17: Logic words? Two brown-eyed parents! THUMBNAIL #5 _____________________________ _____________________________ ________________________ 18) In mice with complete dominance in coat colour, brown (B) is dominant to white (b). The genotypes BB, Bb, and bb represent: A) two genotypes B) two phenotypes C) three phenotypes D) one phenotype _____________________________ _____________________________ ________________________ 19) Mendel's Law of Segregation separates alleles in forming gametes. Beginning with the genotype (Ww), how would these genes be distributed among four sperm cells? A) all W or all w B) many ways as a matter of chance C) WW, Ww, Ww, ww D) two containing w and two containing W _____________________________ _____________________________ ________________________ 25) If incomplete dominance exists between red and white snapdragons, then the correct genotype of a pink flower and the phenotype of a red flowered-parent, respectively, is: A) RW:RR B) RW:parent → red C) pink:RR D) WW:RR Hint for Question 25: After reading (sr) gen 2, did you change the format in how you assigned symbols? (a) BB (b) green (c) YY (d) YB or BY (e) No,the individual would be green (BY) If you wrote the Y first in YB you would continue to do so all through the Punnett square. BY would be equally correct, but then the B would be written first for all green BY's in the question. THUMBNAIL #6 _____________________________ _____________________________ ________________________ 26) If there is a lack of dominance among black and white horses, then the percentage that will be black if a white horse is mated with a gray horse is: A) 0% B) 75% C) 50% D) 25% Hint for Question 26: Note that in codominance or incomplete dominance, it is not necessary to use homozygous for black or white. Since black can only be BB, a heterozygous BW would have the phenotype gray. THUMBNAIL #7 _____________________________ _____________________________ ________________________ 27) In a case of incomplete dominance, pink flowers are produced from the mating of pure four-o'clock plants. Numerical Response Choose the correct allele combination number from the legend for each of the folowing. Number : ___________ ___________ ___________ genotype 4 allele 2 genotype 3 THUMBNAIL #8 _____________________________ _____________________________ ________________________ 28) In a case of incomplete dominance, pink flowers are produced from the mating of pure four-o'clock plants. Numerical Response If a first filial cross mates genotype 3 x genotype 2, then the phenotypic ratio is Answer: ______ : ______ : ______ white pink red THUMBNAIL #9 _____________________________ _____________________________ ________________________ 29) A pea plant that is heterozgous tall and having homozygous green pods has the genotype and phenotype, respectively, of Question 29 options: A) TTGG: height → dwarf; pod colour → green B) TTGg: height → tall; pod colour → yellow C) ttgg: height dwarf; pod colour → yellow (This is a true description of ttgg, but does it answer the question?) D) TtGG: height → tall; pod colour → green Hint for Question 29: If the questions represent an individual parent, each genotype should have two alleles for the first trait, and two alleles for the second trait [4 letters in total]. (a) TTGG; if the symbol T for tallness is written first, then continue with T or t's first all throughout the question. (b) TtGg; both traits exhibit the heterozygous condition (c) ttgg; even if described as yellow dwarf, it is written ttgg as the tall trait has been indicated to be written first. (d) TTGG; even though green is described first, TTGG (e) Ttyy (f) ttGg; are you getting better at forming the genotype in dihybrid inheritance? (g) ttgg (homozygous recessive); used to test if the other parent is homozygous or heterozygous for a trait. THUMBNAIL #10 Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: shakilch on Jan 9, 2013 Content hidden
Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: grade12student!! on Jan 9, 2013 4) In flowers, blue colour is dominant over white petal colour. The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: A) white and black B) Bb and bb C) Bb and white D) BB and bb Hint for Question 4: (a) bb, the same lower case (b) BB, pure is the same as homozygous (c) Bb, heterozygous means one of each (d) bb, the recessive can only be written in one way (e) BB, genotype is the letters, the gene formula (f) blue; heterozygous is added to distract you Locate the Logic word: phenotype THUMBNAIL #1 _____________________________ _____________________________ ________________________ 5) In a wild plant, white flowers are dominant while red is recessive. The phenotype of a homozygous white flower and the genotype of a red flower, respectively, is: A) Ww and WW B) WW and white C) white and Ww D) white and ww Hint for Question 5: (a) ww, any allele letters as lower case (b) Ww, heterozygous; letters must be different (c) WW, homozygous; letters must be the same (d) red; phenotype! (e) an impossibility: if red it has to be ww, homozygous; if it is heterozygous Ww, then it can't be red THUMBNAIL #2 _____________________________ _____________________________ ________________________ 6) If green is dominant to clear seed colour in a plant, then a cross between two plants that are heterozygous for green seed colour can be represented by: A) P1 = Gg x GG B) P1 = GG x GG C) P1 = Gg x Gg D) P1 = GG x gg Hint for Question 6: (a) P1 = ss x Ss (b) P1 = BB x bb (c) P1 = bb x Bb Information: Once symbols are assigned, the next step is to use the information to correctly form the gene formula (genotype) of the parents. Please practice making the following parents. Before you attempt the multiple choice question check the Hint to evaluate your answers. a) Make the parent generation of the homozygous tall tree pollinated by a heterozygous short tree. Shortness is dominant. b) A yellow flower is recessive. Write the parent generation in a cross between homozygous blue and a yellow flower. c) Brown hair is dominant to red hair. Make the parent generation between a red haired mother and a heterozygous brown haired father. _____________________________ _____________________________ ________________________ 9) When conducting his research into the genetics of garden peas, Gregor Mendel crossed true-breeding, yellow-seeded plants with true-breeding, green-seeded plants. He observed that all the F1 generation had yellow seeds. In the F1 generation, the allele for yellow seeds would have been found in: A) about 50% of the female gametes and 50% of the male gametes produced by F1 plants B) all the female gametes and none of the male gametes produced by the F1 plants C) none of the male or female gametes produced by the F1 plants D) all the male gametes and none of the female gametes produced by the F1 plants _____________________________ _____________________________ ________________________ 11) If (Q) represents the gene for a dominant trait and (q) is the recessive allele, and if Qq mates with qq, then: A) 50% of the offspring will be recessive B) all offspring will be of the dominant trait C) all the offspring will be of the recessive trait D) 75% of the offspring will be of the dominant trait _____________________________ _____________________________ ________________________ _____________________________ _____________________________ ________________________ In birds, black feathers are dominant over white feathers. A black hen is mated to a black rooster. Her eggs were saved. Forty-two chicks hatched in an incubator: thirty-one were black and eleven were white. The gene formulas for the two parents and their offspring are: A) P1 = Bb x bb ; F1 genotypes: Bb, bb, Bb, bb B) P1 = BB x Bb_; F1 genotypes: BB, BB, BB C) P1 = BB x bb ; F1 genotypes: BB, bb, Bb D) P1 = Bb x Bb ; F1 genotypes: BB, bb, Bb _____________________________ _____________________________ ________________________ 15) Numerical Response In the crossing genotype 1 with genotype 2, in what proportion of offspring would the recessive phenotype appear? Record your answer as a value from 0 to 1, rounded to two significant digits. Answer: 0.50 THUMBNAIL #3 _____________________________ _____________________________ ________________________ 16) Numerical Response Choose the correct genotype number for each description of an offspring. Genotype number: ____________ ____________ ____________ ____________ Offspring Description: Homozygous Genotype similar to Heterozygous Recessive genotype one of the parents genotype phenotype This question is really easy. I'm sure you can do this on your own. :) THUMBNAIL #4 _____________________________ _____________________________ ________________________ 17) Gray eyes are inherited as a recessive trait. Two brown-eyed individuals had a gray-eyed offspring. Which of the above crosses would result from the genotype of the parents? A) A. B) B. C) C. D) D. Hopefully these will get you started. These questions are really easy once you know how its done. I strongly suggest that you ask your teacher for help on anything you don't understand. Good luck :) Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: HereTOHELP! on Jan 9, 2013 If you still need help on these, let me know by replying back. I'll be happy to help! ;D
Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: SAMH on Jan 9, 2013 Thank you guys! I really appreciate it. :)
I still need help on the rest. Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: EA on Nov 8, 2013 i want to add 2 questions to this thread please.
In case of incomplete dominance, pink flowers are produced from the mating of four-o' clock plants. Choose the correct allele combination number from the legend for each of the following Number: ___________ _____________ ______________ genotype 4 allele 2 genotype 3 thumbnail #1 2. If a filial cross mates genotype 3 x genotype 2, then the phenotypic ratio is Number: __________ ______________ ______________ white pink red I saw these questions in other threads already, but they were not very clear. I wanted to start a fresh Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: Doctor-2-B on Nov 12, 2013 @EA
The picture says that this is a heterozygous cross. That would be an Rr x Rr (allele1 as R on your picture would therefore be incorrect). Answers: 3 (rr) 8 (r) 2 (Rr) Red = 2 "doses" of R (RR), pink = one dose of R (Rr), and white = no doses of R (rr) G3 (Rr) x G2 (Rr): Phenotypic ratios: white:pink:red 1:2:1 12) If two offspring result from the cross Zz x Zz, what is the probability that both will have the same genotype ZZ? A) 1/4 B) 1/8 C) 1/16 D) 1/2 ___________________ ___________________ ___________________ ___________________ ______ 13) If a short pea plant (recessive) is self-pollinating, then the phenotype of the offspring will be: A) 0% short B) 3:1; 3 tall:1 short C) 50 / 50; half short / half tall D) 100% short ___________________ ___________________ ___________________ ___________________ ______ In birds, black feathers are dominant over white feathers. A black hen is mated to a black rooster. Her eggs were saved. Forty-two chicks hatched in an incubator: thirty-one were black and eleven were white. The gene formulas for the two parents and their offspring are: A) P1 = Bb x bb ; F1 genotypes: Bb, bb, Bb, bb B) P1 = BB x Bb_; F1 genotypes: BB, BB, BB C) P1 = BB x bb ; F1 genotypes: BB, bb, Bb D) P1 = Bb x Bb ; F1 genotypes: BB, bb, Bb ___________________ ___________________ ___________________ ___________________ ______ 15) Numerical Response In the crossing genotype 1 with genotype 2, in what proportion of offspring would the recessive phenotype appear? Record your answer as a value from 0 to 1, rounded to two significant digits. Answer: 0 THUMBNAIL #3 ___________________ ___________________ ___________________ ___________________ ______ 16) Numerical Response Choose the correct genotype number for each description of an offspring. Genotype number: ____________ ____________ ____________ ____________ Offspring Description: Homozygous Genotype similar to Heterozygous Recessive genotype one of the parents genotype phenotype THUMBNAIL #4 ___________________ ___________________ ___________________ ___________________ ______ 17) Gray eyes are inherited as a recessive trait. Two brown-eyed individuals had a gray-eyed offspring. Which of the above crosses would result from the genotype of the parents? A) A. B) B. C) C. D) D. Hint for Question 17: Logic words? Two brown-eyed parents! THUMBNAIL #5 ___________________ ___________________ ___________________ ___________________ ______ 18) In mice with complete dominance in coat colour, brown (B) is dominant to white (b). The genotypes BB, Bb, and bb represent: A) two genotypes B) two phenotypes C) three phenotypes D) one phenotype ___________________ ___________________ ___________________ ___________________ ______ 19) Mendel's Law of Segregation separates alleles in forming gametes. Beginning with the genotype (Ww), how would these genes be distributed among four sperm cells? A) all W or all w B) many ways as a matter of chance C) WW, Ww, Ww, ww D) two containing w and two containing W ___________________ ___________________ ___________________ ___________________ ______ 25) If incomplete dominance exists between red and white snapdragons, then the correct genotype of a pink flower and the phenotype of a red flowered-parent, respectively, is: A) RW:RR B) RW:parent → red C) pink:RR D) WW:RR Hint for Question 25: After reading (sr) gen 2, did you change the format in how you assigned symbols? (a) BB (b) green (c) YY (d) YB or BY (e) No,the individual would be green (BY) If you wrote the Y first in YB you would continue to do so all through the Punnett square. BY would be equally correct, but then the B would be written first for all green BY's in the question. THUMBNAIL #6 ___________________ ___________________ ___________________ ___________________ ______ 26) If there is a lack of dominance among black and white horses, then the percentage that will be black if a white horse is mated with a gray horse is: A) 0% B) 75% C) 50% D) 25% Hint for Question 26: Note that in codominance or incomplete dominance, it is not necessary to use homozygous for black or white. Since black can only be BB, a heterozygous BW would have the phenotype gray. (WW x BW doesn't produce any BB) Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: lpirija on Apr 13, 2014 Question. 27 - In case of incomplete dominance, pink flowers are produced from the mating of pure four-oclock plants. Choose the correct allele combination number from the legend for each of the following.******* I think the answer is as follows, because in incomplete dominance the letters(symbols) need to be in upper case************
genotype 4 - Answer is 5 WW allele 2 - Answer is 9 W genotype 3 - Answer is 4 RW ********Any suggestions from anyone else?????****** Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: briiabbxo on May 1, 2014 5) In a wild plant, white flowers are dominant while red is recessive. The phenotype of a homozygous white flower and the genotype of a red flower, respectively, is: A) Ww and WW B) WW and white C) white and Ww D) white and ww Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: MissImpulsive on Jun 24, 2014 Thanks for these answers!
Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: salllysfh on Jul 26, 2014 Thanks
Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: blazin_wolf on Aug 18, 2014 #27 I believe the answer is actually in order 382. look at the details of the question. I believe the line "In a case of incomplete dominance, pink flowers are produced from the mating of pure four-o'clock plants" is there as a distractor to fool you. This line is irrelevant to the question as PURE "true breeding" parents would have homozygous genotypes. The questions information however says P1 Generation is a heterozygous cross not homozygous. and the given information for each parent is R. therefor parents to be heterozygous would be Rr. The question would clearly state otherwise that the P1 generation was a Incomplete Dominant Heterozygous cross to begin with. that additional line about incomplete dominance has no relevance to this question if you think about it. The Parents aren't "pure" they are heterozygous.... just my analysis of the question... will know once my assignment is graded :sweating:
thanks Got confirmation from my teacher the correct answer #27 594 and #28 1:2:1 Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: Vilma57 on Nov 3, 2014 used the information given in the previous problem. A cross is made between a red flower and a pink flower. What is expected probability for the various colors
Title: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is: Post by: ILoveBIO30 on Apr 3, 2015 Whats the answer to question 6?
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is Post by: ILoveBIO30 on Jun 20, 2015 Does anyone know if 6 is correct?
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is Post by: Farheen98 on May 1, 2016 WHAT IS THE ANSWER FOR Q:26???
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, ... Post by: ahn chorva on Feb 28, 2020 thanks
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, ... Post by: Cassidy Tuttle on May 6, 2020 thank you
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, is Post by: Cassidy Tuttle on May 6, 2020 thank you for the answer
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, ... Post by: Shun Empire on Oct 27, 2020 16. 2112
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, ... Post by: Heather MAMGODIBAYE on Dec 10, 2020 thank you
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, ... Post by: reese gabriel on Dec 10, 2020 thanks
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, ... Post by: millena1016 on Dec 30, 2020 tyyy
Title: Re: The genotype of a heterozygous blue flower and the phenotype of a white flower, respectively, ... Post by: Alyssa Alcantara on Mar 2, 2021 thank youu
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