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Title: Betelgeuse is a star in the constellation Orion. It radiates heat at the rate of 3.00 × 1030 W and ... Post by: Brelou on Feb 24, 2017 Betelgeuse is a star in the constellation Orion. It radiates heat at the rate of 3.00 × 1030 W and has a surface temperature of 3000 K. Assuming that it is a perfect emitter, what is the radius of Betelgeuse? The Stefan-Boltzmann constant is 5.67 x 10-8 W/(m2•K4).
A) 7.80 × 1010 m B) 8.70 × 1010 m C) 1.40 × 1011 m D) 1.90 × 1011 m E) 2.30 × 1011 m Title: Re: Betelgeuse is a star in the constellation Orion. It radiates heat at the rate of 3.00 × 1030 W ... Post by: Raj.S on Feb 24, 2017 Content hidden
Title: Re: Betelgeuse is a star in the constellation Orion. It radiates heat at the rate of 3.00 × 1030 W ... Post by: bio_man on Nov 8, 2021 Quote A giant star has a surface temperature of 3000 K and the radiant power emitted by the star is 6 x 1030 W. Assume that the star is a perfect emitter and that it is spherical. What is the radius of the star? Stefan Boltzmann constant \(\sigma \)= 5.67x10^-8 W/m^2.K T = 3000 K, P = 6x1030 W From Stefan Boltzman law for perfect emitter Power emitted by giant star is P = \(\sigma\)AsT4 6x1030 = (5.67*10-8)(4x3.14xR2)(3000)4 Radius of stat R = 3.225x1011 m |