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Title: Considering the limiting reactant concept, how many moles of copper(I) sulfide are produced from t Post by: shellysearle on Apr 19, 2017 Considering the limiting reactant concept, how many moles of copper(I) sulfide are produced from the reaction of 0.500 mol of copper and 0.750 mol of sulfur? 2 Cu(s) + S(s) rightwards arrow Cu2S(s) Title: Re: Considering the limiting reactant concept, how many moles of copper(I) sulfide are produced .. Post by: bio_man on Apr 19, 2017 The balanced equation for the reaction is:
2Cu + S --> Cu2S 2 mol Cu reacts with 1 mol S to make 1 mol Cu2S First, find the limiting reagent. Assume all the Cu is used up. 3 mol Cu x (1 mol S / 2 mol Cu ) = 1.5 mol S required. Since there is only 1 mol S and 1.5 mol S is required to use up all the Cu, S is the limiting reagent. Use S to calculate the amount of product formed. 1 mol S x (1 mol Cu2S / 1 mol S) = 1 mol Cu2S |