|
Title: How many miligrams of pyruvate (MW=110g/mol) are needed in order to make 40mL of 5.0mM pyruvate ... Post by: steffiebee on Apr 30, 2017 How many miligrams of pyruvate (MW=110g/mol) are needed in order to make 40mL of 5.0mM
pyruvate solution? Show all work and include appropriate units. This is part of an LDH lab. I've sat here for hours and tried to figure it out. I know that I have to convert 5mM to moles, which is .005 moles. And 40ml is .04L. What's next? Title: Re: How many miligrams of pyruvate (MW=110g/mol) are needed in order to make 40mL of 5.0mM pyruvate ... Post by: Sam_M on Nov 5, 2020 Hi. That is a simple general chemistry problem.
[A] = n/v n=m/MW where [A] is the molar concentration of solute , n is the amount of moles and v is the volume of your solution. m is the mass of the solute and MW the molar weight. ==> m = [A] * v * MW m (g) = (5 * 10^-3 mol/L) * (0.4 L) * (110 g/mol) = 0.22 g = 220 mg of pyruvate |