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Title: Hot to get molarity of HCL Post by: Tx29 on Jul 9, 2017 Calculate the molarity of Hydrochloric acid solution in the original 25mL sample..the molarity of NaOH is 0.1M.
Sample data table. Molarity of base = 0.1M Volume of acid = 25mL Final buret reading = 35.7mL Initial buret reading = 50.0mL Volume of base used = 14.3mL Please, show me step by step of how to solve this as I have more to complete.. Thanks in advance. Title: Re: Hot to get molarity of HCL Post by: bolbol on Jul 10, 2017 HCl + NaOH ----> NaCl + H2O
Molarity = mol/L Volume of base (NaOH) = initial buret reading (50.0mL) - final buret reading (35.7mL) = 14.3 mL volume of base used to neutralize 25mL of HCl n = molarity of base (NaOH) x volume of base in L Covert mL to L 1L = 1000mL n = 0.1 M x 0.0143 L = 0.00143 mole of NaOH Molarity of HCl = 0.00143 mole / 0.025 L= 0.0572 M of HCl |