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Title: Chem 3 Post by: mazda215 on Oct 25, 2010 ok so i need help on these two questions..
1.Calculate the molarity of a solution that contains 5.35g NaCI in a 220 ML solution 2.What mass of Glucose C6H1206 is required to prepare 500 ML of a 2.50 M solution? can anyone explain clearly on how to do these two problems? thanks if anyone answers Title: Re: Chem 3 Post by: bio_man on Oct 25, 2010 For 1.
Find moles: NaCI = 5.35g / 58.443 g/mol (molar mass) = # moles M = molality = # moles / 0.220 Kg of water = # (your answer) Title: Re: Chem 3 Post by: mazda215 on Oct 25, 2010 so would it be .416M NaCl?....and any idea on the second question?
Title: Re: Chem 3 Post by: bio_man on Oct 26, 2010 Exactly... :) Not sure about the second one though...
Title: Re: Chem 3 Post by: chemb on Oct 26, 2010 First find the molar mass of glucose... so find carbon * 6... hydrogen * 12 ... and oxygen * 6
so: molar mass (g/mol) * 0.500 L * 2.50 mol / L you get molar mass (g/mol) * 0.500 L * 2.50 mol / L Cool? |