Biology Forums - Study Force

1. Examine the three diagrams of hypothetical moose populations. What are the two different distribution patterns shown?

2. The shaded parts of the diagrams represent the transects that were used to sample each population. calculate the area per transect. (1.0 cm represents 1.0km)
    Hint: Area per transect is length x width. Use a ruler.

3. For each hypothetical population, count the moose within each transect

4. For each hypothetical population, calculate the average number of moose per transect

5. Calculate the average density of each hypothetical moose

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This has been asked so often and no one has been able to tackle it. Thanks for taking the time to answer it.

Hi ! I have a question for number 2, what did you measure for the length ? Was it only the parts that's not shaded?

Post Merge: 10 years ago

Oooooh ! I'm sorry, that was stupid. I get it now! Thanks so much! :D

Do you mind posting the answer?

I'll post the answers as soon as I get my papers back. I'm in doubt about question 5.
I'm not sure if I need to count the moose on each diagram and use that for the equation or just the ones on the transects. ~_~

Thank you!  :)

Post Merge: 10 years ago

Please correct me if I am wrong but #5 should be....

Pattern 1: Dp = 4.7moose/4.8km2  Dp = 0.98 moose/km2
Pattern 2: Dp = 7.3 moose/4.8km2  Dp = 1.5 moose/km2
Pattern 3: Dp = 8.5 moose/4.8km2  Dp  = 1.77 moose/km2

.....should it not?

Were these answers correct?

Don't know yet sorry, I'll post the correct answers when get them back ;)

Okay these are the correct answers, sorry, made a mistake above.

Pattern 1: Dp = 4.7moose/4.8km2  Dp = 0.98 moose/km2
Pattern 2: Dp = 7.3 moose/4.8km2  Dp = 1.5 moose/km2
Pattern 3: Dp = 9.8 moose/4.8km2 Dp = 2.0 moose/km2

Thank you so much for the answers in the comments. Helps a lot.

Thank you

thanks

Excuse me if I’m wrong, but doesn’t pattern 3 have 59 moos in all 6 transects. From the first transect to the last it’s 9, 20, 5, 14, 8 and 3. 9+20+5+14+8+3=59. Thus 59/6=9.8 followed by the Dp which is 9.8/4.8km2 =2.04 = 2

(https://biology-forums.com/gallery/45/6_29_05_22_12_01_01.png) (https://biology-forums.com/index.php?action=gallery;sa=view&id=45148)

(https://biology-forums.com/gallery/45/6_28_05_22_11_59_19.png) (https://biology-forums.com/index.php?action=gallery;sa=view&id=45145)

1) the distribution pattern 1 &2 have three transects but distribution pattern 3 have six transects .

​​​​​​2) distribution pattern 1 &2 have equal area per transcet,

but distribution pattern 3 has double area compared to 1&2 .

3) distribution pattern 1 - 14 moose in 3 transects

distribution pattern 2 - 22 mooses in 3 transcets

distribution pattern 3 - 60 moose in 6 transcets

4) distribution pattern 1 - 14/3 - 4.6 average

distribution pattern 2 - 22/3 - 7.33 average

distribution pattern 3 - 60/6 - 10 average  

5) if we assume 1 transcet = 1km area ,  

on average density of population is  

4.6 per km in pattern 1 .

same as above average numbers

Thanks!