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Title: Genetics -- Recombination Frequencies & Gene Mapping Post by: zgrami on Jun 22, 2013 I got an answer (12,5,17) but I want to confirm... I am a bit uneasy -- I tend to get 16.4 instead of 17?
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: biolove on Jun 22, 2013 what does the question read ?
what did you get ? Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: colleen on Jun 23, 2013 what does the question read ? zgrami mentions that in the original posting --> 12,5,17. Problem is, the image is so tiny I can't read the writing :( Do you mind writing out the question ? Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: duddy on Jun 24, 2013 Always post the question word for word:
You plant 1000 tomato seeds resulting from the cross, and get the following results: (data attached) Use the data to complete the linkage map below. Drag the labels onto the chromosome diagram to identify the locations of and distances between the genes. Use the blue labels and blue targets for the genes; use the white labels and white targets for the distances. Gene m has already been placed on the linkage map. The first thing to do in a trihybrid testcross problem is identify your parental and double cross over classes, ie. the highest and lowest progeny classes. In this case, your parental classes are MDP and mdp. The double cross over classes are mDp and MdP. The gene in the middle is the one that “flips” between parental and double cross over classes. In this case, you can see that D changes while M and P are constant. Therefore, D is in the middle and the order is MDP. A cross over between M and D would produce the progeny classes Mdp and mDP. Add the number of these cross overs to the number of double cross overs, and divide by the total progeny: (52+62+2+4)/1000=0.12, or 12 map units. Doing the same for D and P should give you 0.05, or 5 map units. This means the distance between M and P would be 12+5=17 map units. Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: ochorios on Jun 24, 2013 I could be wrong :P
parental a) MDP and b) mdp c) MmDdPp d) Mdp and e) mDP. (52+62+2+4)/1000=0.12, or 12 map units. Doing the same for D and P should give you 0.05, or 5 map units. Distance between M and P would be 12+5=17 map unit Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: lizbet17 on Oct 31, 2013 Content hidden
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: rolandorules on Nov 3, 2013 thank you
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: jaditya on Nov 10, 2013 thank you
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: horveyy on Nov 13, 2013 thank you guys! this is exactly correct!
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: gabbieg0502 on Nov 20, 2013 Thanks!
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: videogames on Nov 30, 2013 a) 12
b) 5 c) 17 d) d e) p Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: huydeebird on Dec 9, 2013 Thanks!!!
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: ashleyrael on Jan 31, 2014 I got an answer (12,5,17) but I want to confirm... I am a bit uneasy -- I tend to get 16.4 instead of 17? Thank you!Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: bioforumzrool on Feb 12, 2014 Thank you!
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: amishkhan9 on Mar 13, 2014 thanks
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: mdutoit95 on May 14, 2014 This is the correct answer.
a) 12 b)5 c)15.8 d) d e) p Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: mhdevine on Jun 2, 2014 Thank you!
Title: Re: Genetics -- Recombination Frequencies & Gene Mapping Post by: elaissia on Sep 18, 2014 Genetics is killing me right now... Thanks.
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