|
Title: Precalc help? graphing inequality? Post by: !JRon@n on Oct 3, 2013 x^2-1 is less than or equal to the absolute value of x + 1. so it basically looks like this:
x^2-1 (less than or equal to) lx+1l i hate precalculus. i'm a sophomore for gods sake. Title: Re: Precalc help? graphing inequality? Post by: AzzidReign on Oct 6, 2013 I'm sorry if I don't see this, but where is the question?
Title: Re: Precalc help? graphing inequality? Post by: bio_man on Oct 6, 2013 Do you want us to graph this for you?
Title: Re: Precalc help? graphing inequality? Post by: padre on Oct 6, 2013 x^2-1 <= lx+1l
Move all variables and constants to one side: x2 - 1 - x - 1 <= 0 x2 - x - 2 <= 0 I could be wrong :s |