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Title: Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions. The wires are ... Post by: kph2015 on Oct 23, 2013 Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions. The wires are separated by 0.20 m. What is the magnetic field midway between the two wires?
5.0×10-5 T 2.0×10-5 T 3.0×10-5 T 4.0×10-5 T 1.0×10-5 T Title: Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions. The wires are ... Post by: padre on Oct 23, 2013 Magnetic field due to a wire is proportional to I/R. [B = (M0)I / 2(pi)R]
So, setting B1 = B2 and canceling constants, we get I1 / R1 = I2 / R2 20(R2) = 5(R1) R1 = 4(R2) So, it should be 4 times further from the wire carrying 20A, or 4/5 of the distance separating the wires. r = .8 * .20m = .16m (from the 20A wire) Hope that helps |