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beardy beardy
wrote...
Posts: 166
10 years ago
I'm having trouble simplifying this, please help with steps.

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Hi

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Donated
Valued Member
10 years ago
About the best I can do is find a LCD of 16π and then I get this:

\(\frac{{\pi}{x^{2}}+4{x^{2}}-28{\pi}x+196{\pi}}{16{\pi}}\).

Here's the "scratchwork" for that:

LCD of 4π and 16: 16π.

Since the first denominator is 4π and 16π/4π = 4, we must multiply the numerator by 4:
\(\frac{4{x^{2}}}{16{\pi}}\)

Since the second denominator is 16 and 16π/16 = π, we must multiply the numerator by π:
\(\frac{{\pi}(196-28x+{x^{2}})}{16{\pi}}\).

Now that we have an LCD, we can combine the numerators:
\(\frac{4{x^{2}}+{\pi}(196-28x+{x^{2}})}{16{\pi}}\)

Distribute the pi:
\(\frac{4{x^{2}}+(196{\pi}-28{\pi}x+{\pi}{x^{2}})}{16{\pi}}\)

Rearrange the terms from highest to lowest polynomial degree:

\(\frac{{\pi}{x^{2}}+4{x^{2}}-28{\pi}x+196{\pi}}{16{\pi}}\)

OR

\(\frac{4{x^{2}}+{\pi}{x^{2}}-28{\pi}x+196{\pi}}{16{\pi}}\)

Minor, but some would argue that the 4x2 should come first.  Either way, that's about all I can see that can be done with this expression...
Pretty fly for a SciGuy
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