× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
g
3
3
2
J
2
p
2
m
2
h
2
s
2
r
2
d
2
l
2
a
2
New Topic  
imn0tokei imn0tokei
wrote...
Posts: 3
Rep: 0 0
10 years ago
A population of a species exhibits logistic growth. If the carrying capacity is 200 individuals
and r = 0.3 individuals/(individuals per month), what is the maximum population growth rate for
the population? Show all your work.
Read 790 times
2 Replies

Related Topics

Replies
wrote...
10 years ago
Thank you this really helped me on my assignment!! Keep it up Slight Smile
wrote...
Educator
7 years ago
For a population of species which exhibits logistic growth, population growth rate can be calculated using the following equation:

dN/dt = rN ( 1- N/K)

Where dN/dt – Population growth rate

             K – Carrying capacity

              r – Rate of individuals per month

              N – Population size

Maximum growth rate occurs when population size is half of the carrying capacity of the habitat (N = K/2).

In the given situation

K = 240 individuals

N = K / 2 = 240 / 2 = 120

r = 0.3 individuals per month

Maximum population logistic growth rate for the population can be calculated as follows:

dN/dt = rN ( 1- N/K)

dN/dt = 0.3 x 120 (1 – 120/ 240)

dN/dt = 36 (1 – 0.5)

dN/dt = 36 x 0.5

dN/dt = 18 individuals per month
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1163 People Browsing
 108 Signed Up Today
Related Images
  
 669
  
 1150
  
 1163
Your Opinion
What's your favorite math subject?
Votes: 293