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keelyhawkins keelyhawkins
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Posts: 652
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5 years ago
If a 330  resistor dissipates 2 W, its voltage drop equals ________.
 
  A) 660 V B) 2.57 V C) 6.6 V D) 25.7 V
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nino99nino99
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5 years ago
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D

Given:
Resistance (R) = 330 Ω
Power (P) = 2 W

Use the formula for power (P = V * I) to find the current (I):

2 W = V * I
Rearrange the formula to solve for I:

I = 2 W / V
Use Ohm's Law (V = I * R) to find the voltage (V):

V = I * 330 Ω
Substitute the value of I from step 2 into the equation from step 3:

V = (2 W / V) * 330 Ω
Simplify:

V^2 = 660 WΩ
Take the square root of both sides to find V:

V ≈ √(660 WΩ)
Calculate the approximate value:

V ≈ 25.7 V
1

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Anonymous
wrote...
2 months ago
Help! The answer is missing an explanation...
wrote...
2 months ago
Done!
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