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Home Q & A Board Science-Related Homework Help Engineering Electrical Engineering
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lexilourdes lexilourdes
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5 years ago
If a 4.7 k resistor and 2.2 k resistor are connected in parallel, the total resistance is ________.
 
  A) 2200  B) 4700
  C) greater than 2200  D) less than 2200
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AshleyroshellAshleyroshell
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5 years ago
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D

Excerpt
When resistors are connected in parallel, you can calculate the total resistance using the following formula:

1 / Rt = (1 / R1) + (1 / R2)

Where:

Rt is the total resistance
R1 is the resistance of the first resistor
R2 is the resistance of the second resistor
In this case, R1 is 4.7 kΩ (kiloohms) and R2 is 2.2 kΩ.

Let's calculate it:

1 / Rt = (1 / 4.7 kΩ) + (1 / 2.2 kΩ)

Now, calculate the values on the right side:

1 / Rt = (1 / 4700 Ω) + (1 / 2200 Ω)

Now, add these fractions:

1 / Rt = (2200 + 4700) / (4700 * 2200)

1 / Rt = 6900 / 10340000

Now, find the reciprocal to get Rt:

Rt = 10340000 / 6900 ≈ 1497.10 Ω

So, the total resistance when a 4.7 kΩ resistor and a 2.2 kΩ resistor are connected in parallel is approximately 1497.10 Ω, which is less than 2200 Ω.

So, the correct answer is:

D) less than 2200
This verified answer contains over 160 words.
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Anonymous
wrote...
#2
2 months ago
Help! The answer is missing an explanation...
wrote...
#3
2 months ago
Done!
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