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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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fodog414 fodog414
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Posts: 279
Rep: 26 0
9 years ago
The electron configuration of a particular diatomic species is
 (sigma2s)^2 (anti-bonding sigma*2s)^2 (sigma 2p)^2 (pi2p)^4 (anti-bonding pi*2p)^1
 What is the bond
order for this species?
A) 4
B) 3.5
C) 3
D) 2.5
E) 2


could someone explain the pi2p^4 orbit? Is that supposed to be pi2p^2?
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7 Replies
Replies
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#1
Educator
9 years ago
Hey fodog414, see if the answer can be found in one of the two attachments. Answers are at the end of the document in case you're wondering!
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fodog414 Author
wrote...
#2
9 years ago
No luck :/ but thank you for looking!
Answer accepted by topic starter
skip5284skip5284
wrote...
#3
Posts: 159
Rep: 21 0
9 years ago
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fodog414 Author
wrote...
#4
9 years ago
I think i have a small handle on MO diagrams but i'm just getting confused on the pi2p^4 does that ^4 signify 4 electrons in the orbit?
wrote...
#5
Educator
9 years ago
Hey fodog414, could you provide us an update on the solution to this?
fodog414 Author
wrote...
#6
9 years ago
Ya of course I thought I replied to all the questions

Its actually quite easy

there are 8 bonding electrons and there are 3 antibonding electrons

so its 8-3/2

which is 2.5
D
wrote...
#7
Educator
9 years ago
Oh nice, so skip5284 was right! Will mark as solved.
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