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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Stringfield73 Stringfield73
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6 years ago

At 99, the vapor pressure of water is 733 mm Hg.
  (a) At standard atmospheric pressure, what is the vapor pressure of a compound being
  steam-distilled at this temperature?
  (b) If the compound has a molecular weight of 180, how much water is required to distill 1.0 g
  of the compound?

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#1
6 years ago

(a) Ptotal = P A + P B
If P A (water) is 733 mm and Ptotal is 760, then P B (the compound being distilled) is (760
733) or 27 mm.
(b) (wtA/wtB) = (P A/P B) x (MWA/MWB)
wtA = 1.0 x (733/27) x (18/180) = 2.7 g of water

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